SOLVED IT !!!
'order by max(score)' does the trick!
8-)
On 02/07/2010 11:12, Sebastian Proost wrote:
My two cents
SELECT * FROM (SELECT name, max(score) as m_score
FROM table
GROUP BY name ) AS a ORDER BY m_score DESC LIMIT 0,3
Kenny Billiau schreef:
Ow that sucks :/
.. but what is wrong?
On Fri, 2 Jul 2010, Frederik Delaere wrote:
doesn't give correct results :(
Kenny Billiau wrote:
If you want the unique rows, use
distinct.
If you want the highest score
per person, you'll have to use group by with an aggregate
function ;)
SELECT name, max(score)
FROM table
GROUP BY name
ORDER BY score DESC
LIMIT 0,3
Kenny
On Fri, 2 Jul 2010, Lieven Sterck wrote:
SELECT DISTINCT name, score FROM
.....
djebus, even I know that !! 8-)
On 02/07/2010 10:23, Frederik Delaere wrote:
lets say I have this data
id name score
1 dude1 9.1
2 dude2 9.5
3 dudette1 9.0
4 dude1 9.3
5 dudette1 8.5
And I want to select highest 3 scores:
SELECT score FROM table ORDER BY score DESC LIMIT 0,3
result will be
9.5
9.3
9.1
but how can I select both the name and the score and I
only want one
score per person
I can do: SELECT DISTINCT name FROM table ORDER BY score
DESC LIMIT 0,3
this will give me the correct names in the correct
order, but I want
their score also
is this possible in one query ?
thanksuwel !
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Sebastian Proost, PhD Student
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Lieven Sterck, PhD
Tel:+32 (0)9 3313821 Fax:+32 (0)9 3313809
VIB Department of Plant Systems Biology, UGent
Bioinformatics and Evolutionary Genomics Division
Technologiepark 927, B-9052 Gent, Belgium
Email: lieven.sterck@psb.vib-ugent.be
Website: http://bioinformatics.psb.ugent.be
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